问题
我们需要编写一个 JavaScript 函数,它将数学表达式作为字符串接收,并将其结果作为数字返回。
我们需要支持以下数学运算符 –
-
除法 /(作为浮点除法)
-
加法 + p>
-
减法 –
-
乘法 *
运算符始终根据从左到右,* 和 / 必须在 + 和 – 之前计算。
示例
以下是代码 –
实时演示
const exp = '6 - 4'; const findResult = (exp = '') => { const digits = '0123456789.'; const operators = ['+', '-', '*', '/', 'negate']; const legend = { '+': { pred: 2, func: (a, b) => { return a + b; }, assoc: "left" }, '-'&: { pred: 2, func: (a, b) => { return a - b; }, assoc: "left" }, '*': { pred: 3, func: (a, b) => { return a * b; }, assoc: "left" }, '/': { pred: 3, func: (a, b) => { if (b != 0) { return a / b; } else { return 0; } } }, assoc: "left", 'negate': { pred: 4, func: (a) => { return -1 * a; }, assoc: "right" } }; exp = exp.replace(/s/g, ''); let operations = []; let outputQueue = []; let ind = 0; let str = ''; while (ind < exp.length) { let ch = exp[ind]; if (operators.includes(ch)) { if (str !== '') { outputQueue.push(new Number(str)); str = ''; } if (ch === '-') { if (ind == 0) { ch = 'negate'; } else { let nextCh = exp[ind+1]; let prevCh = exp[ind-1]; if ((digits.includes(nextCh) || nextCh === '(' || nextCh === '-') && (operators.includes(prevCh) || exp[ind-1] === '(')) { ch = 'negate'; } } } if (operations.length > 0) { let topOper = operations[operations.length - 1]; while (operations.length > 0 && legend[topOper] && ((legend[ch].assoc === 'left' && legend[ch].pred <= legend[topOper].pred) || (legend[ch].assoc === 'right' && legend[ch].pred < legend[topOper].pred))) { outputQueue.push(operations.pop()); topOper = operations[operations.length - 1]; } } operations.push(ch); } else if (digits.includes(ch)) { str += ch } else if (ch === '(') { operations.push(ch); } else if (ch === ')') { if (str !== '') { outputQueue.push(new Number(str)); str = ''; } while (operations.length > 0 && operations[operations.length - 1] !== '(') { outputQueue.push(operations.pop()); } if (operations.length > 0) { operations.pop(); } } ind++; } if (str !== '') { outputQueue.push(new Number(str)); } outputQueue = outputQueue.concat(operations.reverse()) let res = []; while (outputQueue.length > 0) { let ch = outputQueue.shift(); if (operators.includes(ch)) { let num1, num2, subResult; if (ch === 'negate') { res.push(legend[ch].func(res.pop())); } else { let [num2, num1] = [res.pop(), res.pop()]; res.push(legend[ch].func(num1, num2)); } } else { res.push(ch); } } return res.pop().valueOf(); }; console.log(findResult(exp));
输出
2
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码农资源网 » 在 JavaScript 中考虑运算符优先级评估数学表达式