实现双向链表
admin 阅读:107 2024-09-04
假设理解 big o 表示法。 javascript 中有示例。资料参考 gayle laakmann mcdowell 的《cracking the coding interview》
理解双向链表
双向链表与单链表非常相似,除了节点的结构和添加/删除节点的方式不同。
节点结构 双向链表中的节点包含prev指针、next指针和value。 prev 指针指向前一个节点,next 指针指向下一个节点。本质上,这个列表在每个节点都是双向的。
添加节点 在特定索引处插入新节点(newnode):- 将当前位于插入索引处的节点存储在临时变量 nextnode 中。
- 更新前一个节点和新节点的连接:
- 将前一个节点的next指针设置为newnode。
- 设置newnode的prev指针指向前一个节点。
- 将新节点连接到下一个节点:
- 将newnode的next指针设置为nextnode。
- 将 nextnode 的 prev 指针设置为 newnode。
- 更新前一个节点的next指针:
- 设置为指向被移除后的节点。
更新下一个节点的prev指针:
- 将其设置为指向被删除节点之前的节点。
- 在双向链表中添加/删除 →
css">o(n)o(n)o(n)
- 在双向链表的头部或尾部添加/删除 →
o(1)o(1)o(1)
class listnode {
constructor(value, prev = null, next = null) {
this.value = value;
this.prev = prev;
this.next = next;
}
}
class doublylinkedlist {
constructor() {
this.head = null;
this.tail = null;
this.size = 0;
}
// add a node to the head of the list
addhead(value) {
const newnode = new listnode(value, null, this.head);
if (this.head) {
this.head.prev = newnode;
} else {
this.tail = newnode; // if list was empty, new node is also the tail
}
this.head = newnode;
this.size++;
}
// add a node to the tail of the list
addtail(value) {
const newnode = new listnode(value, this.tail, null);
if (this.tail) {
this.tail.next = newnode;
} else {
this.head = newnode; // if list was empty, new node is also the head
}
this.tail = newnode;
this.size++;
}
// remove a node from the head of the list
removehead() {
if (!this.head) return null; // list is empty
const removedvalue = this.head.value;
this.head = this.head.next;
if (this.head) {
this.head.prev = null;
} else {
this.tail = null; // list became empty
}
this.size--;
return removedvalue;
}
// remove a node from the tail of the list
removetail() {
if (!this.tail) return null; // list is empty
const removedvalue = this.tail.value;
this.tail = this.tail.prev;
if (this.tail) {
this.tail.next = null;
} else {
this.head = null; // list became empty
}
this.size--;
return removedvalue;
}
// remove a node at a specific index
removeat(index) {
if (index = this.size) return null;
let current;
if (index index; i--) {
current = current.prev;
}
}
if (current.prev) current.prev.next = current.next;
if (current.next) current.next.prev = current.prev;
if (index === 0) this.head = current.next;
if (index === this.size - 1) this.tail = current.prev;
this.size--;
return current.value;
}
// get the size of the list
getsize() {
return this.size;
}
// get the values in the list
getvalues() {
const values = [];
let current = this.head;
while (current) {
values.push(current.value);
current = current.next;
}
return values;
}
}
函数式面向对象编程
function ListNode(value, prev = null, next = null) {
this.value = value;
this.prev = prev;
this.next = next;
}
function DoublyLinkedList() {
this.head = null;
this.tail = null;
this.size = 0;
}
// Add a node to the head of the list
DoublyLinkedList.prototype.addHead = function(value) {
const newNode = new ListNode(value, null, this.head);
if (this.head) {
this.head.prev = newNode;
} else {
this.tail = newNode;
}
this.head = newNode;
this.size++;
};
// Add a node to the tail of the list
DoublyLinkedList.prototype.addTail = function(value) {
const newNode = new ListNode(value, this.tail, null);
if (this.tail) {
this.tail.next = newNode;
} else {
this.head = newNode;
}
this.tail = newNode;
this.size++;
};
// Remove a node from the head of the list
DoublyLinkedList.prototype.removeHead = function() {
if (!this.head) return null;
const removedValue = this.head.value;
this.head = this.head.next;
if (this.head) {
this.head.prev = null;
} else {
this.tail = null;
}
this.size--;
return removedValue;
};
// Remove a node from the tail of the list
DoublyLinkedList.prototype.removeTail = function() {
if (!this.tail) return null;
const removedValue = this.tail.value;
this.tail = this.tail.prev;
if (this.tail) {
this.tail.next = null;
} else {
this.head = null;
}
this.size--;
return removedValue;
};
// Remove a node at a specific index
DoublyLinkedList.prototype.removeAt = function(index) {
if (index = this.size) return null;
let current;
if (index index; i--) {
current = current.prev;
}
}
if (current.prev) current.prev.next = current.next;
if (current.next) current.next.prev = current.prev;
if (index === 0) this.head = current.next;
if (index === this.size - 1) this.tail = current.prev;
this.size--;
return current.value;
};
// Get the size of the list
DoublyLinkedList.prototype.getSize = function() {
return this.size;
};
// Get the values in the list
DoublyLinkedList.prototype.getValues = function() {
const values = [];
let current = this.head;
while (current) {
values.push(current.value);
current = current.next;
}
return values;
};
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